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Can "exactly 2 heads" and "exactly 2 tails" overlap?
Think about it: if you flip 3 coins and get exactly 2 heads (like HHT), you automatically have exactly 1 tail. You can't have exactly 2 of BOTH!
Conclusion: These events are mutually exclusive. No overlap to worry about.
Why does this matter?
Since "exactly 2 heads" and "exactly 2 tails" can't happen together, we can simply add their probabilities. No subtraction needed!
Flip a fair coin 3 times. What's P(exactly 2 heads OR exactly 2 tails)?
Sample space (2³ = 8 outcomes):
Count outcomes with exactly 2 heads
HHT, HTH, THH = 3 outcomes
Count outcomes with exactly 2 tails
HTT, THT, TTH = 3 outcomes
Check: Is there any overlap?
No! The sets {HHT, HTH, THH} and {HTT, THT, TTH} have no common elements. P(A ∩ B) = 0 (mutually exclusive).
Add probabilities (no overlap to subtract)
Result:
✓ Verification: 6 highlighted outcomes out of 8 total = 6/8 = 75% ✓
"Exactly n" events are often mutually exclusive because you can't have two different exact counts simultaneously. When you see "exactly X OR exactly Y", first check if they can overlap. If not, just add the probabilities!